Strategic Analysis Paper
1. If you
have access to SPSS, compute the Shapiro-Wilk test of normality for the
variable age (as demonstrated in Exercise 26). If you do not have access to
SPSS, plot the frequency distributions by hand. What do the results indicate?
The correlation value P is 0.357, the results
indicates that the frequency distribution does was not derived from normal variables.
P value is greater than alpha P > 0.05. Such case indicates that it is not
statistically significant.
2. State
the null hypothesis where age at enrollment is used to predict the time for
completion of an RN to BSN program.
Age at enrollment does not predict the completion of
an RN to BSN program
3. What is
b as computed by hand (or using SPSS)?
b = 0.047
4. What is
a as computed by hand (or using SPSS)? See chart in #3
A = 11.763
5. Write
the new regression equation.
Y = bx + a
Y = 0.047x + 11.76
6. How
would you characterize the magnitude of the obtained R2 value? Provide a
rationale for your answer.
According to analysis the magnitude of the value of
R2 is expected to be small according to description provided within the lesson
7. How much
variance in months to RN to BSN program completion is explained by knowing the
student’s enrollment age?
Having knowledge of student’s enrollment age, gives
explanation of variance in months of RN to BSN program completion, which is
calculated as 1.2%?
8. What was
the correlation between the actual values and the predicted values using the
new regression equation in the example?
Using new regression equation, the correlation value
between actual y values and predicted y values is 0.108
9. Write
your interpretation of the results as you would in an APA-formatted journal.
A study research using linear regression with
student age as the predictor and duration of months to complete the RN to BSN
program we obtain values of beta as = 0.108, p = 0.651, and R2 = 1.2% The
findings obtained reveal that student age at the during enrollment time does
not provide accurate prediction on how long specific student take to complete
the program
10. Given
the results of your analyses, would you use the calculated regression equation
to predict future students’ program completion Time by using enrollment age as
x? Provide a rationale for your answer
No
The results obtained when using the calculated
regression equation is not accurate. It is small hence cannot provide desirable
results.
Predicted value for youngest student
Y= 0.047x + 11.763 where x = 23
Y = 0.047 * 23 + 11.763
Y = 1.081 + 11.763
Y = 12.844
Predicted value for oldest student
Y = 0.047 * 51 +11.763
Y = 2.397 + 11.763
Y = 14.16
The difference for youngest and the oldest are very
insignificant using the equation
Exercise 35
1. Do the
example data in Table 35-2 meet the assumptions for the Pearson χ 2 test?
Provide a rationale for your answer
Yes the data meets the assumptions of Pearson χ 2
tests which includes
Data have nominal-level or are frequency data
The sample
size is adequate
Measures are independent of each other
Subject's data only fit into one category
2. Compute
the χ 2 test. What is the χ 2 value?
X2 = 11.931
3. Is the χ
2 significant at α = 0.05? Specify how you arrived at your answer.
Yes, χ2 is significant. Since the p value is =
0.001, which is less than alpha α = 0.05
4. If using
SPSS, what is the exact likelihood of obtaining the χ2value at least as extreme
as or as close to the one that was actually observed, assuming that the null
hypothesis is true?
Assuming that the null hypothesis is true, the
specific likelihood of obtaining a χ2 values as extreme as possible or as close
as possible to the value observed. is 0.1%
5. Using
the numbers in the contingency table, calculate the percentage of antibiotic
users who tested positive for candiduria.
The percentage of antibiotic users who tested
positive for candiduria is given by
15 / 58 = 0.259
= 0.259 * 100 %
= 25.9 %.
6. Using
the numbers in the contingency table, calculate the percentage of non-antibiotic
users who tested positive for candiduria.
Percentage of antibiotic users tested positive for
candiduria is given by
0 / 39 = 0
= 0 * 100 %
= 0 %
7. Using
the numbers in the contingency table, calculate the percentage of veterans with
candiduria who had a history of antibiotic use.
The percentage of veterans with candiduria who had a
history of antibiotic use is given by
15 /15 = 1
= 1 * 100 %
= 100%
8. Using
the numbers in the contingency table, calculate the percentage of veterans with
candiduria who had no history of antibiotic use.
The percentage of veterans with candiduria who had
no history of antibiotic use given by 0 / 15 = 0
= 0 * 100 %
= 0 %
9. Write
your interpretation of the results as you would in an APA-formatted journal.
The analysis based on Pearson χ2 revealed that
antibiotic users comprising of 25 % of the sample had higher rate of candiduria
infections than those who did not use antibiotics comprising of 0 % of the
sample, χ2(1) = 11.931, p = 0.001. Results obtained shows that antibiotic
consumption increases risk for developing candiduria.
10. Was the
sample size adequate to detect differences between the two groups in this example?
Provide a rationale for your answer.
Yes
The sample size was adequate for effective detecting
of differences between the two groups. The significant difference was p =
0.001, the value is smaller than alpha = 0.05
Sherry Roberts is the author of this paper. A senior editor at MeldaResearch.Com in urgent custom research papers. If you need a similar paper you can place your order from nursing school papers services.
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